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OUTPUT CURVES

ID versus VDS

triode saturation VDS → ID ↑ boundary: VDS = VGS − Vth each curve = one VGS Below Vth (cutoff) the current is near zero, so no curve is drawn.

Fix the gate voltage, sweep the drain voltage, and record the drain current. Each curve is one gate voltage. Current first rises along a curve, then flattens once the channel pinches off near the drain.

Higher gate voltage, taller curve: that's the gate controlling the current.

THREE REGIONS

Cutoff, triode, saturation

Cutoff · VGS < Vth No inversion channel, only a tiny leakage current
Triode · VDS < VGS − Vth The channel spans source to drain, acting like a voltage-controlled resistor
Saturation · VDS ≥ VGS − Vth The channel pinches off near the drain and the current flattens
VGS − Vth is called the overdrive voltage.

TRIODE REGION

A tunable resistor

ID = k(VGS−Vth)VDS

For small VDS the current is proportional to VDS, with k = μ·Cox·(W/L). The full expression is ID = k[(VGS − Vth)·VDS − VDS²/2]. More gate overdrive lowers the effective resistance, so the gate tunes the resistance.

In triode, the MOSFET is a resistor whose value the gate sets.

SATURATION REGION

A gate-controlled current source

ID = ½k(VGS−Vth)²

Once the channel pinches off, the current depends on the gate, not the drain. Example: with μCox = 100 µA/V², W/L = 10, and an overdrive of 0.5 V, the saturation current is ½ × 100 µA/V² × 10 × 0.25 V² = 125 µA.

Square law: doubling the overdrive quadruples the current.

UNIT 6 STUDY COMPLETE

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Ready for the Fab Challenge?

You've covered cutoff, triode, and saturation, with the square-law equations.